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Date: 30-12-2021
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Date: 2-1-2022
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Date: 26-12-2021
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Let and
be sets. Conditional probability requires that
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(1) |
where denotes intersection ("and"), and also that
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(2) |
Therefore,
![]() |
(3) |
Now, let
![]() |
(4) |
so is an event in
and
for
, then
![]() |
(5) |
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(6) |
But this can be written
![]() |
(7) |
so
![]() |
(8) |
(Papoulis 1984, pp. 38-39).
RFERENCES:
Papoulis, A. "Bayes' Theorem in Statistics" and "Bayes' Theorem in Statistics (Reexamined)." §3-5 and 4-4 in Probability, Random Variables, and Stochastic Processes, 2nd ed. New York: McGraw-Hill, pp. 38-39, 78-81, and 112-114, 1984.
Press, W. H.; Flannery, B. P.; Teukolsky, S. A.; and Vetterling, W. T. Numerical Recipes in FORTRAN: The Art of Scientific Computing, 2nd ed. Cambridge, England: Cambridge University Press, p. 810, 1992.
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