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Date: 1-8-2016
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Date: 4-9-2016
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Date: 9-8-2016
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Shallow Water Waves
Water waves travel on the surface of a large lake of depth d. The lake has a perfectly smooth bottom and the waves are propagating purely in the +z direction (The wave fronts are straight lines parallel to the x axis. See Figure 1.1).
Figure 1.1
a) Find an expression for the velocity of the water v (y, z, t).
b) Find the corresponding dispersion relation. You may assume that the flow of the water is irrotational that the amplitude of the waves is small (in practice, this means that v2 << gh, where h is the height of the waves), that surface tension effects are not important, and that water is incompressible.
c) Find the group velocity of the wave front and consider two limiting cases λ >> d, λ << d.
SOLUTION
We essentially follow their solution. In this problem, we consider an incompressible fluid (which implies that the density is constant (see Figure 1.2). We also consider irrotational flow and ignore the surface tension and viscosity of the fluid. This is a very idealized case. In this case,
Figure 1.2
we have and since ρ is constant, Combining this equation with the condition allows us to introduce a potential φ (the so-called potential flow). The velocity v may be written in the form and for the potential we have
(1)
On the bottom, we have the boundary condition
(2)
Using Euler’s equation for an irrotational field
(3)
(Here p is pressure, is the acceleration of gravity.) We substitute and rewrite (3) as
(4)
Since (4) is the gradient of a function, the function itself will simply be
where f(t) is some arbitrary function of time which may be chosen to be zero. Also taking into account that v2/2 << gh, we have
Or
(5)
Consider the surface of the unperturbed water at y = d and introduce a small vertical displacement Y = y – d. Also, we assume that there is a constant pressure on the surface of the water p. Then from (5) we obtain
(6)
The constant p0 + ρgd can be eliminated by using another gauge for φ:
We now obtain from (6)
(7)
Again using the fact that the amplitude of the waves is small, we can write vy = ∂Y/∂t. In the same approximation of small oscillations, we can take the derivative at y = d. On the other hand, vy = ∂φ/∂y. So, from (7)
(8)
Now look for a solution for φ in the form φ = f(y) cos (kz – ωt). Substituting this into (1) gives
(9)
so
(10)
where A, B are arbitrary constants. From (2), we find that A = B and φ = A' cos h ky . cos(kz – ωt) where A' = 2A. By differentiating the potential we obtain the velocity components
b) From (8) we get the dispersion relation:
(11)
(12)
c) The group velocity of the waves is
(13)
Consider two limiting cases:
1) kd >> 1, d >> λ short wavelength waves. Then
2) kd << 1, d << λ long wavelength waves. Then
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مخاطر خفية لمكون شائع في مشروبات الطاقة والمكملات الغذائية
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"آبل" تشغّل نظامها الجديد للذكاء الاصطناعي على أجهزتها
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تستخدم لأول مرة... مستشفى الإمام زين العابدين (ع) التابع للعتبة الحسينية يعتمد تقنيات حديثة في تثبيت الكسور المعقدة
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